Matematika

Pertanyaan

\frac{x}{x-3} - \frac{2}{x^ -4x+3{2} }

1 Jawaban

  • [tex]\displaystyle \frac{x}{x-3} - \frac{2}{x^2 -4x+3}=\frac{x}{x-3} - \frac{2}{(x-1)(x-3)} \\ \frac{x(x-1)}{(x-3)(x-1)}-\frac{2}{(x-3)(x-1)}=\frac{x^2-x-2}{x^2-4x+3}[/tex]

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