Tolong ini bagaimana caranya

f(x) = (1 + x)³(x² - x + 1)^5
u = (1 + x)³ >>> u' = 3(1 + x)²
v = (x² - x + 1)^5 >>> v' = 5(x² - x + 1)^4(2x - 1)
v' = 5(2x - 1)(x² - x + 1)^4
f'(x) = u'v + v'u
= 3(1 + x)²(x² - x + 1)^5 + 5(2x - 1)(x² - 1 + 1)^4(1 + x)³
f'(1) = 3(1 + 1)²(1 - 1 + 1)^5 + 5(2 - 1)(1 - 1 + 1)^4(1 + 1)³
= 3(2)²(1) + 5(1)(1)(2)³
= 52