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Pertanyaan

jika tetapan asam CH3COOH=10-5, maka larutan CH3COOK 0,0q M....

1 Jawaban

  • pH = 1/2 (14 + pKa + log[G])
    pH = 1/2 (14 + (-log10^-5) + log10^-2
    pH = 1/2 (14 + 5 - 2)
    pH = 1/2 (17)
    pH = 8,5

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