bantu jawab dong butuh cepet jawaban nya, sama caranya

Bab Turunan

f(x) = ([tex] x + \frac{3}{x} [/tex])([tex] x - \frac{2}{x} [/tex])
f(x) = [tex] x^{2} - 2 + 3 - \frac{6}{ x^{2} } [/tex]
f(x) = [tex] x^{2} - 6. x^{-2} + 1[/tex]
f'(x) = [tex] 2.x^{2-1} - (-2)6. x^{-2-1} + 0.1. x^{0-1} [/tex]
f'(x) = [tex]2x + 12 x^{-3} [/tex]
f'(x) = [tex]2x + \frac{12}{ x^{3} } [/tex]