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Pertanyaan

garis 4x-3y=10 menyinggung lingkaran : x^2+y^2+6x-2y=15 di titik...

1 Jawaban

  • 4x - 3y = 10 => 4x = 3y + 10 => x = (3y + 10)/4
    x^2 + y^2 + 6x - 2y = 15
    ((3y + 10)/4)^2 + y^2 + 6(3y + 10)/4 - 2y = 15
    (9y^2 + 60y + 100)/16 + y^2 + (18y + 60)/4 - 2y = 15 ===> kali 16
    9y^2 + 60y + 100 + 16y^2 + 72y + 240 - 32y = 240
    25y^2 + 100y + 100 = 0
    y^2 + 4y + 4 = 0
    (y + 2)(y + 2) = 0
    y = -2
    x = (3y + 10)/4 = (3(-2) + 10)/4 = 4/4 = 1
    Jadi titik singgungnya (1, -2)

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