persamaan garis lurus yg melalui titik(-3,4) dan (2,-6)

[tex] \frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1} \\ \frac{y - 4}{-6 - 4} = \frac{x + 3}{2 + 3} \\ \frac{y - 4}{-10} = \frac{x + 3}{5} \\ 5y - 20 = -10x - 30 \\ 5y = -10x - 10 \\ y = -2x - 2[/tex]