tentukan nilai minimum fungsi dari f(x)=12 sinx +5 cos x+3

minimum jika f'(x) = 0

f'(x) = 0
12cosx - 5sinx = 0
5sinx = 12cosx
sinx/cosx = 12/5
tan x = 12/5

gunakan segitiga siku siku utk menentukan sin x dan cos x

tan x = 12/5 <=== DE = 12 , SA = 5
MI^2 = 12^2 + 5^2 = 144+25 = 169
MI = akar169
MI = 13

sin x = DE/MI = 12/13
cos x = SA/MI = 5/13

substitusi ke persamaan awal
f(x) = 12sin x + 5cosx + 3
fmin = 12×12/13 + 5×5/13 + 39/13
fmin = 144/13 + 25/13 + 39/13
fmin = 208/13

smg mbantu
maaf kalo salah