tolong jawabb yaa makasihh

Lim x (cos6x - 1) / sinx . tan²2x
x→0

Lim (cos6x - 1) / tan²2x
x→0

Lim (1 - 2sin²3x - 1)
x→0 .. / (2tanx/1 - tan²x)²

Lim -2sin²3x (1 - tan²x)²
x→0 .. / (2tanx)²

Lim -sin²3x (1 - tan²x)²
x→0 .. / tan²x

Lim - 3 (1 - tan²x)²
x→0

= -3 (1 - tan0)²

= -3 (1 - 0)²

= -3 (1)

= -3