Tolong dibantu teman beserta pakai caranya juga ya. Terimakasih!!

1. f(x)= x²+1, g(x)= x+3
a .(f+g)(x)= f(x)+g(x)= (x²+1) + (x+3)= x²+x+4
(f+g)(2)= (2²)+(2)+4= 4+2+4= 10
b. (f-g)(x)= f(x)-g(x)= (x²+1)-(x+3)= x²+1-x-3= x²-x-2
(f-g)(-2)= (-2²)-(-2)-2= 4+4-2= 6
c. f¹(x)= 2x, g¹(x)= 1
(f×g)(x)= f(x)×g(x)= [f¹(x)×g(x)]+[f(x)×g¹(x)]= [2x(x+3)]+[(x²+1)1]= [2x²+6x]+[x²+1]= 2x²+6x+x²+1= 3x²+6x+1.
(f×g)(1)= 3(-1)²+6(1)+1= 3+6+1= 10
d. f¹(x)= 2x, g¹(x)= 1
[f÷g](x)= f(x)÷g(x)= [f¹(x)×g(x)]-[f(x)×g¹(x)] / [(f(x))²]= {[2x(x+3)]-[(x²+1)1]} / [(x²+1)²]=
{[2x²+6x]-[x²+1]} / [(x²+1)²]= {2x²+6x-x²-1} / [(x²+1)²]= {x²+6x-1} / [(x²+1)²]
[f÷g](-1)= {(-1)²+6(-1)-1} / {[(-1)²+1)]²}= (1-6-1) / (1+1)²= -6/(2²)= -6/4= -3/2
e. ?
f. ?

maaf y cuma bisa jawab segini.

good luck
:-)
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