jika f(x)=x^2 + 1 dan g(x)==x+2/2, maka nilai (f•g)(2) adalah... *ini caranya langsung masukkan g ke f nya atau masukkan nilai 2 nya dulu ke g?

Langsung aja y

(fog)(x) = f{g(x)}

= g(x)² + 1
= (x+2 / 2)² + 1
= (x² + 4x + 4 / 4) + 1
= (x² + 4x + 4 + 4) / 4
= (x² + 4x + 8) / 4

(fog)(2) = (2² + 4.2 + 8) / 4
(fog)(2) = (4 + 8 + 8) / 4
(fog)(2) = 20 / 4
(fog)(2) = 5

semoga berguna +_+

(f o g)(2) = f(g(2))
= f((2 + 2)/2)
= f(4/2)
= f(2)
= 2^2 + 1
= 4 + 1
= 5