tentukan kemolaran larutan yg mengandung 10 gram nacl dalam 200 ml air (ar na =23,cl =35,5)

Molar = Gr/Ar * 1000/ml
= 10/59 * 1000/200
= 10/59 * 5/1
=50/59
= 0,85 m/l

massa NaCl = 20 gram
Volume = 200 mL = 0,2 liter
Mr NaCl
= Ar Na + Ar Cl
= 23 + 35,5
= 58,5

n NaCl
= massa / Mr
= 10 / 58,5
= 0,17 mol


M = [tex] \frac{n}{L} [/tex]
M = [tex] \frac{0,17}{0,2} [/tex]
M = 0,85 M