jika cosec a=13/12 dan a lancip,tentukan sin a dan ctg a

sisi depan = 12
sisi miring = 13
sisi samping = akar 13²-12² = 5

maka
sin a = 12/13
ctg a = 5/12

Bab Trigonometri
Matematika SMA Kelas X

cosec = 13/12 = r/y

x = √(r² - y²)
x = √(13² - 12²)
x = √(169 - 144)
x = √25
x = 5

sin a = y/r = 12/13

ctg a = x/y = 5/12