68 derajat Fahrenheit =................derajat kelvin
Matematika
ridani3
Pertanyaan
68 derajat Fahrenheit =................derajat kelvin
2 Jawaban
-
1. Jawaban andhikahanif
68 °F
= 5/9 x 68 - 32 + 273
= 37,8 - 32 + 273
= 5,8 + 273
= 278,8 °K -
2. Jawaban Gaby08
68°F
=5/9X68-32+273
=37,8-32+273
=5,8+273
278,8°K