SBMPTN

Pertanyaan

nomer 2 tolong ya, thanks
nomer 2 tolong ya, thanks

1 Jawaban

  • Misal laju v dan jarak s : v = s/t => s = v.t
    1) jika lajunya bertambah 3 km/jam, sampai 40 menit lebih cepat = 2/3 jam
    s = (v + 3).(t - 2/3)
    s = vt - 2/3 v + 3t - 2
    s = s - 2/3 v + 3t - 2
    2/3 v - 3t = -2

    2) jika laju berkurang 2 km/jam, sampai 40 menit lebih lambat = 2/3 jam
    s = (v - 2)(t + 2/3)
    s = vt + 2/3 v - 2t - 4/3
    s = s + 2/3 v - 2t - 4/3
    -2/3 v + 2t = -4/3

    Eliminasi
    2/3 v - 3t = -2
    -2/3 v + 2t = -4/3
    --------------------- +
    -t = -10/3
    t = 10/3 jam

    2/3 v - 3t = -2
    2/3 v - 3(10/3) = -2
    2/3 v - 10 = -2
    2/3 v = 8
    v = 8 . 3/2 = 12 km/jam

    Jarak = s = vt = 12 km/jam . 10/3 jam = 40 km