carilah nilai x dari turunan fungsi : f(x) = 2/3x^3 - 3x² + 1, apa bila f'(x) = 4 nb : ^ = pangkat 2/3x^3 = dua per tiga x pangkat 3

f(x) = 2/3x^3 - 3x² + 1
f'(x) = 4

f'(x) = 2/3 x^-3 - 3x^2 + 1
f'(x) = 2/3 (3) x^-3-1 - 3(2)x^2-1 + 0
f'(x) = 2x^-4 - 6x^1
f'(x) = 2/x^4 - 6x
f'(x) = 4
f'(x) = 2/ 4^4 - 6.4
f'(x) = 2 / 256 - 24
= 1/128 -24
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