3x-4 / x^2-x-6 = (A/x-3) + (B/x+2) tentukan A & B HELP

Pecahan parsial,
[tex]\displaystyle \frac{3x-4}{x^2-x-6}=\frac{A}{x-3}+\frac{B}{x+2} = \frac{A(x+2)+B(x-3)}{(x^2-x-6} \\ \frac{3x-4}{x^2-x-6}=\frac{Ax+2A+Bx-3B}{x^2-x-6}=\frac{(A+B)x+(2A-3B)}{x^2-x-6} \\ \\ A+B = 3 \\ 2A-3B=-4 \\ $Didapat : $A=1,B=2[/tex]

(3x - 4) / (x + 2)(x - 3) = A/(x - 3) + B/(x + 2)
(3x - 4) / (x + 2)(x - 3) = ((A + B)x + (2A - 3B)) / (x + 2)(x - 3)

A + B = 3     | x 2|
2A - 3B = - 4 | x 1|
______________ -
5B = 10
B = 2
A = 1