cos x = -3/5 tan x > 0 sin x + cot x + sec x = .....

Bab Trigonometri
Matematika SMA Kelas X

cos bernilai negatif dan tan bernilai positif, maka terletak di kuadran III

x = a
cos a = -3/5 = x/r

y = √(r² - x²)
y = √(5² - (-3)²)
y = √(25 - 9)
y = 4

sin a + cot a + sec a
= y/r + x/y + r/x
= - 4/5 + 3/4 - 5/3
= (-48 + 45 - 100)/60
= -103/60
= - 1 43/60