nilai maksimum f (x) = -2x^2 + x+6
Matematika
ditafebriami
Pertanyaan
nilai maksimum f (x) = -2x^2 + x+6
1 Jawaban
-
1. Jawaban keruasriki
x = -b/2a
x = -1/2(-2)
x = -1/-4
x = 1/4
nilai maks
f(1/4) = -2×(1/4)^2 + 1/4 + 6
f(1/4) = -2 × 1/16 + 1/4 + 6
f(1/4) = -1/8 + 1/4 + 6
f(1/4) = -3/24 + 6/24 + 4/24
f(1/4) = 7/24