lim (x^2 -1) sin 6x : x^3 + 3x^2 + 2x dimana x→0=
Matematika
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Pertanyaan
lim (x^2 -1) sin 6x : x^3 + 3x^2 + 2x dimana x→0=
1 Jawaban
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1. Jawaban DB45
Limit bentuk 0/0
lim(x-->0) (x²-1) . sin 6x / (x³+3x²+2x)
= lim(x->0) (x+1)(x-1). sin 6x. / (x)(x+1)(x+2)
= lim(x->0 sin 6x/x . (x-1)/(x+2)
x= 0
= 6. (-1)/(2)
= - 3
..