Jika f(x-2)=x^2 + 1 dan g(x)= 3x-1 Maka gof(3) adalah

Bab Fungsi

Misalkan
x - 2 = 3
Maka
x = 5

f(x - 2) = x^2 + 1
f(3) = 5^2 + 1
f(3) = 25 + 1
f(3) = 26

(g o f)(3)
= g(f(3))
= g(26)
= 3(26) - 1
= 78 - 1
= 77

(g o f ) (x) = (g(fx))
= 2(2x-3) + 1
= 4x-6+1
= 4x-5
g(2) = 4(2)-5
= 3

Jadikan saya terbaik