Dik f(x) = 2x+5 G(x) = 1/3x+2 x ≠2/3 Dit gof(1) =? A.-16/6 B.-14/6 C.-12/6 D.-10/6 E.-8/6

=> g○f(1)
=> g(f(1))
=> g(2×1 + 5)
=> g(2+5)
=> g(7)
=> 1/(3×7 +2)
=> 1/23

Jwb. F

coba cek g(x) nya...

gof(x)= g(f(x))
= g(2x + 5)
= 1/3(2x + 5) + 2(2x + 5)
= 2/3x + 5/3 + 4x + 10
= 2/3x + 4x +5/3 + 10
= 14/3x + 35/3
gof(1)= 14/3.1 + 35/3
= 14/3 + 35/3
= 49/3
=16,3....