tolong bantu no 6 & 7...thx
Matematika
tiara1203
Pertanyaan
tolong bantu no 6 & 7...thx
2 Jawaban
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1. Jawaban zahrazahwa
7. 2log5 = p
2log100= 2log(2^2.5^2)
= 2log 2^2+2log5^2
=2 + 2p
(maaf basis 2 di depan) -
2. Jawaban arsetpopeye
6)(3log2√2 + 3log3√3 + 3log36)/(3log24 - 3log4)
= (3log2√2.3√3 + 3log36) / (3log24/4)
= (3log6√6 + 3log36) / (3log6)
= (3log6^3/2 + 3log6^2) / (3log6)
= (3/2 . 3log6 + 2 . 3log6) / (3log6)
= (3/2 + 2)(3log6) / (3log6)
= (1,5 + 2)
= 3,5
7) 2log100 = 2log10^2
= 2 . 2log10
= 2 . 2log(2.5)
= 2 . (2log2 + 2log5)
= 2(1 + p)
= 2 + 2p