Matematika

Pertanyaan

tolong bantu no 6 & 7...thx
tolong bantu no 6 & 7...thx

2 Jawaban

  • 7. 2log5 = p
    2log100= 2log(2^2.5^2)
    = 2log 2^2+2log5^2
    =2 + 2p
    (maaf basis 2 di depan)
  • 6)(3log2√2 + 3log3√3 + 3log36)/(3log24 - 3log4)
    = (3log2√2.3√3 + 3log36) / (3log24/4)
    = (3log6√6 + 3log36) / (3log6)
    = (3log6^3/2 + 3log6^2) / (3log6)
    = (3/2 . 3log6 + 2 . 3log6) / (3log6)
    = (3/2 + 2)(3log6) / (3log6)
    = (1,5 + 2)
    = 3,5

    7) 2log100 = 2log10^2
    = 2 . 2log10
    = 2 . 2log(2.5)
    = 2 . (2log2 + 2log5)
    = 2(1 + p)
    = 2 + 2p