tolong berikan penjelasan dan penjabaran , terima kasih

[ x² + 2px + 4q = 0 ]

b² - 4ac = 0
(2p)² - 4(1)(4q) = 0
4p² - 16q = 0
4p² = 16q
p² = 4q → q = p²/4
p = √4q
p = 2√q

[ x² + 4qx + 2p = 0 ]

b² - 4ac = 0
(4q)² - 4(1)(2p) = 0
16q² - 8p = 0
16q² = 8p
q² = 1/2 p → p = 2q²
q = √1/2p

→ Persamaan :

p = p
2√q = 2q²
(2√q)² = (2q²)²
4q = 4q^4
q^4 = q
q^3 = 1
q = 1

q = q
√1/2p = p²/4
(√1/2p)² = (p² / 4)²
1/2 p = p^4 / 16
2p^4 = 16p
p^3 = 16p / 2p
p^3 = 8
p = 2

→ 2p + 3q :
= 2 (2) + 3(1)
= 4 + 3
= 7