1.Cos 135' - Sin 330' _______________= tan 315' + Cos 225' A.3/2 _/2 B.3_/2-4 C.1/2(3_/2-4) D.1/2(_/2-4) E.(_/2-4) 2.Sec a Tan^2 a + Sec a= A.sec a B.sec^2 a C.
Matematika
vincentsuntoso
Pertanyaan
1.Cos 135' - Sin 330'
_______________=
tan 315' + Cos 225'
A.3/2 _/2
B.3_/2-4
C.1/2(3_/2-4)
D.1/2(_/2-4)
E.(_/2-4)
2.Sec a Tan^2 a + Sec a=
A.sec a
B.sec^2 a
C.sec^3 a
D.cosec a
E.cosec^2 a
mohon bantuan nya terhadam dua soal trigonometri diatas teman teman,terimakasih
_______________=
tan 315' + Cos 225'
A.3/2 _/2
B.3_/2-4
C.1/2(3_/2-4)
D.1/2(_/2-4)
E.(_/2-4)
2.Sec a Tan^2 a + Sec a=
A.sec a
B.sec^2 a
C.sec^3 a
D.cosec a
E.cosec^2 a
mohon bantuan nya terhadam dua soal trigonometri diatas teman teman,terimakasih
1 Jawaban
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1. Jawaban sandysuhendra
1) cos 135 = cos(180-45) = - cos 45 = - ½√2
Sin 330 = sin (360-30) = - sin 30 = - ½
Tan 315 = tan (360-45) = - tan 45 = - 1
Cos 225 = cos (180+45) = - cos 45 = - ½√2
Mk (-½√2 + ½)/(-1 - ½√2) × 2/2
= (-√2 + 1)/(-2 - √2) × (-2 + √2)/(-2 + √2)
= (2√2 - 2 - 2 + √2)/(4-2)
= (3√2 - 4)/2 = ½ (3√2 - 4) (C)
2) sec a ( tan²a + 1)
= sec a ( sec²a)
= sec³a (C)