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Please bantu jawab no.4, soal sbm tahun lalu.
Please bantu jawab no.4, soal sbm tahun lalu.

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1 Jawaban

  • pencerminan pada  y = x - 1  ⇒ k = - 1

    [tex] \left[\begin{array}{ccc}x'\\y'\\\end{array}\right] = \left[\begin{array}{ccc}0&1\\1&0\\\end{array}\right] \left[\begin{array}{ccc}x\\y - k\\\end{array}\right] + \left[\begin{array}{ccc}0\\k\\\end{array}\right] [/tex]
     
    [tex] \left[\begin{array}{ccc}c\\d\\\end{array}\right] = \left[\begin{array}{ccc}0&1\\1&0\\\end{array}\right] \left[\begin{array}{ccc}a\\b + 1\\\end{array}\right] + \left[\begin{array}{ccc}0\\- 1\\\end{array}\right] [/tex]

    [tex] \left[\begin{array}{ccc}c\\d\\\end{array}\right] = \left[\begin{array}{ccc}b +1\\a\\\end{array}\right] + \left[\begin{array}{ccc}0\\-1\\\end{array}\right] [/tex]

    [tex] \left[\begin{array}{ccc}c\\d\\\end{array}\right] = \left[\begin{array}{ccc}b + 1\\a - 1\\\end{array}\right] [/tex]

    c = b + 1     ; dan  d = a - 1

    2c + d = 2 (b + 1) + a - 1
                = 2b + 2 + a - 1
                = 2b + a + 1
                = a + 2b + 1    ....... jawaban : E

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