1. Limit x mendekati 5 x²-25/x⁴-625 2.f(x)=3x-6 maka f'(x)= 3. F(x)=7x/(3x-8) maka f-¹ (x)=

1.
=> (x^2 - 25)/(x^2 + 25)(x^2 - 25)
=> 1/(x^2 + 25)
=> 1/(5^2 + 25)
=> 1/(25+25)
=> 1/50

2.
f'(x) = 3

3.
f-1(x) = 8x/(3x - 7)

1. = (x^2)/(x^2+25)(x^2-25)
    = 1/(x^2+25)
    = 1/(5^2+25)
    = 1/(25+25)
    = 1/50
2.f'(x) = 3 
3.f-1(x) = 8x/(3x-7)
Maaf kalau salah ya