jika (f bundaran g ) (x) = x^2 -2x-2 dan f (x) = x-3. Maka niai g(2) =

(fog)(x) = x² - 2x - 2
f(g(x)) = x² - 2x - 2
g(x) - 3 = x² - 2x - 2
g(x) = x² - 2x - 2 + 3
g(x) = x² - 2x + 1
g(2) = 2² - 2 . 2 + 1
g(2) = 4 - 4 + 1
g(2) = 1

Diketahui (fog)(x) = x^2 - 2x - 2 dan f(x) = (x-3)
Ditanya : g(2)
Jawab :
(fog)(x) = fog(x)
<=>x^2 - 2x - 2 = g(x) - 3
<=>g(x) = x^2 - 2x - 2 + 3
<=>g(x)= x^2 - 2x + 1
<=>g(2)= 2^2 - 2*2+1
<=>g(2)= 4-4+1
g(2)= 1

Jdi g(2)= 1