dik : ∆ PQR < PQR = 30°
Matematika
fiawss
Pertanyaan
dik : ∆ PQR < PQR = 30°
<QPR = 60° pr= 2 cm
tentukan
a. QR
b.L∆PQR
<QPR = 60° pr= 2 cm
tentukan
a. QR
b.L∆PQR
1 Jawaban
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1. Jawaban bapakdr
a) QR/sin<qpr = PR/sin<pqr
QR/sin 60 = 2/sin 30
QR/(√3/2) = 2/(1/2)
QR/(√3/2) = 4
QR = 4 × (√3/2)
QR = 2√3
b) <PRQ = 180 - 30 - 60 = 90
L ∆ = ½.PR.RQ.sin 90
L ∆ = ½.(2).(2√3).(1)
L ∆ = 2√3