bila ksp CaCo3 = 9×10min8 molL min 1 maka berapa gram kelarutan CaCo3 dalam 250ml air (Mr CaCo3 = 100) ?

ksp CaCO3 = [Ca][CO3]
= s x s = s2
s = √ksp
= √9 x 10^-8 = 3 x 10^-4
s = M
M = gram / Mr x 1000/ ml
3x10^-4 = gram / 100 x 1000/250
gram x 4 = 3x10^-4 x 100
gram = 3x10^-2 : 4
= 0.75 x 10^-2 gram