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Bab Limit
Matematika SMA Kelas XI

lim (x - √(4x + 10)/(x² - 25)
x→5

= lim (x² - (4x + 10))/((x² - 25) (x + √(4x + 10)))
   x→5

= lim ((x² - 4x - 10) / ((x + 5) (x - 5) (x + √(4x + 10)))
   lim→5

masukkan nilai 5

= (5² - 4 . 5 - 10) / ((5 + 5) (5 - 5) (5 + √(4 . 5 + 10)))
= -5/0
= -∞