Matematika

Pertanyaan

tolong bantuin pliss
tolong bantuin pliss

2 Jawaban

  • Kalau nggak salah,
    Jika x = 3 9-x^2 per 4- akar dari x+1 

    = 9-(3)^2 per 4 – akar dari 3+1
    = 9-9 per 4 – akar dari 4
    = 0 per 4 – 2
    = 0 per 2
    = 0


  • [tex]\lim_{x \to 3} \frac{9- x^{2}}{ 4 - \sqrt{ x^{2} +7}}[/tex]

    [tex]\lim_{x \to 3} \frac{9- x^{2}}{ 4 - \sqrt{ x^{2} +7}}* \frac{4 + \sqrt{ x^{2} +7}}{4 + \sqrt{ x^{2} +7}} [/tex]

    [tex]\lim_{x \to 3} \frac{(9- x^{2})(4 + \sqrt{ x^{2} +7})}{16 - x^{2} -7}[/tex]

    [tex]\lim_{x \to 3} \frac{(9- x^{2})(4 + \sqrt{ x^{2} +7})}{9 - x^{2}}[/tex]

    [tex]\lim_{x \to 3} (4 + \sqrt{ x^{2} +7})[/tex]

    [tex]= (4 + \sqrt{ 3^{2} +7})[/tex]

    [tex]= (4 + \sqrt{ 9 +7})[/tex]

    [tex]= 4 + \sqrt{ 16}[/tex]

    [tex]= 4 + 4[/tex]

    [tex]= 8[/tex]