tolong bantuin pliss
Matematika
tirtanana
Pertanyaan
tolong bantuin pliss
2 Jawaban
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1. Jawaban Rsmayl
Kalau nggak salah,
Jika x = 3 9-x^2 per 4- akar dari x+1
= 9-(3)^2 per 4 – akar dari 3+1
= 9-9 per 4 – akar dari 4
= 0 per 4 – 2
= 0 per 2
= 0 -
2. Jawaban IcukSugiarto
[tex]\lim_{x \to 3} \frac{9- x^{2}}{ 4 - \sqrt{ x^{2} +7}}[/tex]
[tex]\lim_{x \to 3} \frac{9- x^{2}}{ 4 - \sqrt{ x^{2} +7}}* \frac{4 + \sqrt{ x^{2} +7}}{4 + \sqrt{ x^{2} +7}} [/tex]
[tex]\lim_{x \to 3} \frac{(9- x^{2})(4 + \sqrt{ x^{2} +7})}{16 - x^{2} -7}[/tex]
[tex]\lim_{x \to 3} \frac{(9- x^{2})(4 + \sqrt{ x^{2} +7})}{9 - x^{2}}[/tex]
[tex]\lim_{x \to 3} (4 + \sqrt{ x^{2} +7})[/tex]
[tex]= (4 + \sqrt{ 3^{2} +7})[/tex]
[tex]= (4 + \sqrt{ 9 +7})[/tex]
[tex]= 4 + \sqrt{ 16}[/tex]
[tex]= 4 + 4[/tex]
[tex]= 8[/tex]